[Code] Program Counter

프로그램 카운터 과제는 1초마다 프로세스 수를 표시한다.

EnumProcess 함수를 통해 프로세스의 수를 구하면 된다.

print_less_ten은 내가 개인적으로 만든 함수이다. 

날짜 표시할 때 10이하면 두자리수를 맞춰주지 못하기 때문에 그러한 경우 '0'을 출력하도록 하였다.

#pragma comment( lib, "Psapi.lib" )

#include <windows.h>
#include <tchar.h>
#include <psapi.h>
#include <stdlib.h>
#include <iostream>
#include <time.h>

using namespace std;

void print_less_ten(int n){ // change print style for right format

	if(n<10){
		cout << "0" ;
	}
	
}

int main( void )
{

    DWORD aProcesses[1024]; 
    DWORD cbNeeded; 
    DWORD cProcesses;

	time_t t = time(0);   // set time type
    struct tm * now = localtime( & t ); // get time now

	while(1){

		if ( !EnumProcesses( aProcesses, sizeof(aProcesses), &cbNeeded ) )
			return 1;
		
		// Calculate how many process identifiers were returned.
		cProcesses = cbNeeded / sizeof(DWORD);
		
		t = time(0);
		now = localtime( & t );
	
		cout << (now->tm_year + 1900) << '_'; // print year
		
		print_less_ten(now->tm_mon + 1);
	
		cout << (now->tm_mon + 1) << "_" ;  // print month
		
		print_less_ten(now->tm_mday);
		
		cout << now->tm_mday << " : ";   // print day
		
		print_less_ten(now->tm_hour);

		cout << now->tm_hour << "_" ;    // print hour
		
		print_less_ten(now->tm_min);

		cout << now->tm_min << "_";     // print minute

		print_less_ten((now->tm_sec)+1);

		cout << (now->tm_sec + 1);  // print second
	
		cout << " : " << cProcesses << "\n"; // print processes count
		Sleep(1000);  // number is in milliseconds 1Sec = 1000 MiliSeconds
		
	}
    return 0;
}